12y^2=+19y-18

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Solution for 12y^2=+19y-18 equation: 



12y^2=+19y-18

We move all terms to the left:

12y^2-(+19y-18)=0

We add all the numbers together, and all the variables

12y^2-(19y-18)=0

We get rid of parentheses

12y^2-19y+18=0

a = 12; b = -19; c = +18;
Δ = b2-4ac
Δ = -192-4·12·18
Δ = -503
Delta is less than zero, so there is no solution for the equation

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